(-3)^2+(f+3^2)=2*4+6

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Solution for (-3)^2+(f+3^2)=2*4+6 equation:



(-3)^2+(f+3^2)=2*4+6
We move all terms to the left:
(-3)^2+(f+3^2)-(2*4+6)=0
We add all the numbers together, and all the variables
(f+3^2)+(-3)^2-14=0
We add all the numbers together, and all the variables
(f+3^2)-5=0
We get rid of parentheses
f-5+3^2=0
We add all the numbers together, and all the variables
f+4=0
We move all terms containing f to the left, all other terms to the right
f=-4

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